19x^2+31x-630=0

Solution for 19x^2+31x-630=0 equation:

19x^2+31x-630=0

a = 19; b = 31; c = -630;
Δ = b2-4ac
Δ = 312-4·19·(-630)
Δ = 48841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48841}=221$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-221}{2*19}=\frac{-252}{38}
=-6+12/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+221}{2*19}=\frac{190}{38}
=5
$